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Primary alkyl halide C_4H_9Br (a) reacted with alcoholic KOH to give compound (b).Compound (b) is reacted with HBr to give



Answer -

 (c) which is an isomer of (a). When (a) is reacted with sodiummetal it gives compound (d), C8H18 whichis different from the compound formed when n-butyl bromide is reacted withsodium. Give the structural formula of (a) and write the equations for all thereactions.


Answer

Therefore, compound (a) is either n−butylbromide or isobutyl bromide.

Now, compound (a) reacts with Na metal togive compound (b) of molecular formula, C8H18, which is different from the compound formedwhen n−butyl bromide reacts with Na metal. Hence, compound (a) mustbe isobutyl bromide.

Thus, compound (d) is 2, 5−dimethylhexane.

It is given that compound (a) reacts with alcoholic KOH togive compound (b). Hence, compound (b) is 2−methylpropene.

Also, compound (b) reacts with HBr to give compound (c)which is an isomer of (a). Hence, compound (c) is 2−bromo−2−methylpropane.


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