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Question -

Niobium crystallises inbody-centred cubic structure. If density is 8.55 g cm−3, calculate atomic radius of niobium using its atomic mass 93 u.



Answer -

It is giventhat the density of niobium, d = 8.55 g cm−3

Atomic mass, M = 93 gmol−1

As the lattice is bcctype, the number of atoms per unit cell, z = 2

We also know that, NA = 6.022 × 1023 mol−1

Applying the relation:
                          

= 3.612 × 10−23 cm3

So, a =3.306 × 10−8 cm

For body-centred cubicunit cell:

= 1.432 × 10−8 cm

= 14.32 × 10−9 cm

= 14.32 nm

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