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Question -

If NaCl is doped with 10−3 mol % of SrCl2, what is theconcentration of cation vacancies?



Answer -

It is giventhat NaCl is doped with 10−3 mol% of SrCl2.

This means that 100mol of NaCl is doped with 10−3 mol of SrCl2.

Therefore, 1 mol of NaCl isdoped withmol of SrCl2

= 10−5 mol of SrCl2

Cation vacanciesproduced by one Sr2+ ion = 1

Hence, the concentrationof cation vacancies created by SrCl2 is 6.022 × 108 per mol of NaCl.

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