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Question -

H2S, a toxic gas withrotten egg like smell, is used for the qualitative analysis. If the solubilityof H2S in water at STP is 0.195 m, calculate Henry’s law constant.



Answer -

It is given that thesolubility of H2S in water at STP is 0.195 m, i.e., 0.195 mol of H2Sis dissolved in 1000 g of water.

Molesof water

= 55.56 mol

Mole fraction of H2S, x

= 0.0035

At STP, pressure (p) =0.987 bar

According to Henry’s law:

p = KHx

= 282 bar

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