Question -
Answer -
K+/K = −2.93V, Ag+/Ag= 0.80V,
Hg2+/Hg = 0.79V
Mg2+/Mg = −2.37 V, Cr3+/Cr= − 0.74V
Arrangethese metals in their increasing order of reducing power.
Answer
The lower the reductionpotential, the higher is the reducing power. The given standard electrodepotentials increase in the order of K+/K < Mg2+/Mg< Cr3+/Cr < Hg2+/Hg < Ag+/Ag.
Hence, the reducing power of thegiven metals increases in the following order:
Ag < Hg < Cr < Mg < K