Question -
Answer -
Let the total mass of thesolution be 100 g and the mass of benzene be 30 g.
тИ┤Mass ofcarbon tetrachloride = (100 тИТ 30)g
= 70 g
Molar mass of benzene (C6H6) = (6 ├Ч 12 + 6 ├Ч 1) g molтИТ1
= 78 g molтИТ1
тИ┤Numberof moles of┬а
= 0.3846 mol
Molar mass of carbon tetrachloride (CCl4) = 1 ├Ч 12 + 4 ├Ч 35.5
= 154 g molтИТ1
тИ┤Numberof moles of CCl4
= 0.4545 mol
Thus, the molefraction of C6H6┬аis given as:
