The Total solution for NCERT class 6-12
Calculate┬а(a)┬аmolality┬а(b)┬аmolarityand┬а(c)┬аmole fraction of KI if the density of 20% (mass/mass)aqueous KI is 1.202 g mL-1.
(a)┬аMolarmass of KI = 39 + 127 = 166 g molтИТ1
20% (mass/mass)aqueous┬аsolution of KI means 20 g of KI is present in 100 g of solution.
That is,
20 g of KI is present in (100 тИТ20)┬аg of water = 80 g of water
= 1.506 m
= 1.51 m (approximately)
(b)┬аItis given that the density of the solution = 1.202 g mLтИТ1
= 83.19 mL
= 83.19 ├Ч 10тИТ3┬аL
= 1.45 M
= 0.0263