Question -
Answer -
(i) Bromomethane, Bromoform, Chloromethane, Dibromomethane.
(ii) 1-Chloropropane, Isopropyl chloride, 1-Chlorobutane.
Answer
(i)
For alkyl halides containing the same alkyl group, theboiling point increases with an increase in the atomic mass of the halogenatom.
Since the atomic mass of Br is greater than that of Cl,the boiling point of bromomethane is higher than that of chloromethane.
Further, for alkyl halides containing the same alkylgroup, the boiling point increases with an increase in the number of halides.Therefore, the boiling point of Dibromomethane is higher than that ofchloromethane and bromomethane, but lower than that of bromoform.
Hence, the given set of compounds can be arranged in theorder of their increasing boiling points as:
Chloromethane < Bromomethane < Dibromomethane
(ii)
For alkyl halides containing the same halide, the boilingpoint increases with an increase in the size of the alkyl group. Thus, theboiling point of 1-chlorobutane is higher than that of isopropyl chloride and1-chloropropane.
Further, the boiling point decreases with an increase inbranching in the chain. Thus, the boiling point of isopropyl alcohol is lowerthan that of 1-chloropropane.
Hence, the given set of compounds can be arranged in theincreasing order of their boiling points as:
Isopropyl chloride < 1-Chloropropane <1-Chlorobutane