Question -
Answer -
It is given that density of the element, d =2.7 × 103 kg m−3
Molar mass, M = 2.7 × 10−2 kgmol−1
Edge length, a = 405 pm =405 × 10−12 m
= 4.05 × 10−10 m
It is known that, Avogadro’s number, NA =6.022 × 1023 mol−1
Applying the relation,
This implies that four atoms of the element arepresent per unit cell. Hence, the unit cell is face-centred cubic (fcc)or cubic close-packed (ccp).