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Question -

An aqueous solution of 2%non-volatile solute exerts a pressure of 1.004 bar at the normal boiling pointof the solvent. What is the molar mass of the solute?



Answer -

Here,

Vapour pressure of the solutionat normal boiling point (p1) = 1.004 bar

Vapourpressure of pure water at normal boiling point 

Mass of solute, (w2)= 2 g

Mass of solvent (water), (w1)= 98 g

Molar mass of solvent (water), (M1)= 18 g mol−1

According to Raoult’s law,

= 41.35 g mol−1

Hence, the molar mass of thesolute is 41.35 g mol−1.

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