MENU
Question -

An antifreeze solution isprepared from 222.6 g of ethylene glycol (C2H6O2)and 200 g of water. Calculate the molality of the solution. If the density ofthe solution is 1.072 g mLтИТ1, then what shall be the molarity of thesolution?



Answer -

Molar mass of ethylene glycol= 2 ├Ч 12 + 6 ├Ч 1 + 2 ├Ч16

= 62 gmolтИТ1

Numberof moles of ethylene glycol
= 3.59 mol
Therefore,molality of the solution┬а= 17.95 m

Total mass of the solution =(222.6 + 200) g

= 422.6 g

Given,

Density of the solution = 1.072 gmLтИТ1

Volume of the solution

= 394.22 mL

= 0.3942 ├Ч 10тИТ3┬аL

┬аMolarity of thesolution┬а

= 9.11 M

Comment(S)

Show all Coment

Leave a Comment

Free - Previous Years Question Papers
Any questions? Ask us!
×