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Question -

What amount of heat must be supplied to 2.0 × 10-2 kg of nitrogen (at room temperature) to raise its temperature by 45 °C at constant pressure? (Molecular mass of N2 = 28; R = 8.3 J mol-1 K-1.)



Answer -

Given,

Mass of nitrogen = 2 x 10-2 kg

= 20 g

Rise in temperature = ΔT

= 450 C

Heat required = Q =?

Q = nCT

We know,

C = 7R / 2 (diatomic molecule)

C = 7 x 8.3 / 2

n (no. of moles) = w / m

where,

w = 20 g

m = 28 u

n = 20 / 28

n = 1/ 1.4 moles

Let the temperature be 45 K

Q = 10 / 14 x 7 / 2 x 8.3 x 45

We get,

Q = 933.75 J

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