MENU
Question -

Two sitar strings A and B playing the note ‘Ga’ are slightly out of tune and produce beats of frequency 6 Hz. The tension in the string A is slightly reduced and the beat frequency is found to reduce to 3 Hz. If the original frequency of A is 324 Hz, what is the frequency of B?



Answer -

Frequency of string A, fA =324 Hz

Frequency of string B = fB

Beat’s frequency, n = 6 Hz

Frequency decreases with a decrease in the tension in astring. This is because frequency is directly proportional to the square rootof tension. It is given as:

Comment(S)

Show all Coment

Leave a Comment

Free - Previous Years Question Papers
Any questions? Ask us!
NodeJS Interview Questions Answers
ASP.Net Interview Questions Answers
Interview Questions Answers
×