Question -
Answer -
10.5 m
Density of mercury, ρ1 = 13.6 × 103 kg/m3
Height of the mercury column, h1 =0.76 m
Density of French wine, ρ2 = 984 kg/m3
Height of the French wine column = h2
Acceleration due to gravity, g = 9.8 m/s2
The pressure in both the columns is equal, i.e.,
Pressure in the mercury column = Pressure in the French winecolumn
= 10.5 m
Hence, the height of the French wine column for normal atmosphericpressure is 10.5 m.