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Question -

The-electrical resistance in ohms of a certain thermometer varies with temperature according to the approximate law: R = R0 [1+ α (T – T0)].
The resistances is 101.6 Ωat the triple-point of water 273.16 K, and 165.5 Ωat the normal melting point of lead (600.5 K).What is the temperature when the resistance is 123.4 Ω ?



Answer -

Here, R0 = 101.6 Ω; T0 = 273.16 K Case(i) R1= 165.5 Ω; T1 = 600.5 K, Case (ii) R2 =123.4 , T2 = ?
Using the relation R = R0[1 + α (T – T0)]
Case (i) 165.5 = 101.6 [1 + α (600.5 – 273.16)]

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