MENU
Question -

The cylindrical tube of a spray pump has a cross-section of 8.0 cm2 oneend of which has 40 fine holes each of diameter 1.0 mm. If the liquid flowinside the tube is 1.5 m min–1, what is the speed of ejection of theliquid through the holes?



Answer -

Area of cross-section of the spray pump, A1 =8 cm= 8 × 10–4 m2

Number of holes, n = 40

Diameter of each hole, d = 1 mm = 1 × 10–3 m

Radius of each hole, r = d/2 = 0.5 ×10–3 m

Area of cross-section of each hole, = πr=π (0.5 × 10–3)2 m2

Total area of 40 holes, An × a

= 40 × π (0.5 × 10–3)2 m2

= 31.41 × 10–6 m2

Speed of flow of liquid inside the tube, V=1.5 m/min = 0.025 m/s

Speed of ejection of liquid through the holes = V2

According to the law of continuity, we have:

= 0.633 m/s

Therefore, the speed of ejection of the liquid through the holesis 0.633 m/s.

Comment(S)

Show all Coment

Leave a Comment

Free - Previous Years Question Papers
Any questions? Ask us!
×