Question -
Answer -
Answer: 9.8 × 102 Pa
Length of the horizontal tube, l = 1.5 m
Radius of the tube, r = 1 cm = 0.01 m
Diameter of the tube, d = 2r = 0.02 m
Glycerine is flowing at a rate of 4.0 × 10–3 kg s–1.
M = 4.0 × 10–3 kgs–1
Density of glycerine, ρ = 1.3 × 103 kgm–3
Viscosity of glycerine, η = 0.83 Pa s
Volume of glycerine flowing per sec:
= 3.08 × 10–6 m3 s–1
According to Poiseville’s formula, we have the relation for therate of flow:
Where, p is the pressure difference between thetwo ends of the tube
= 9.8 × 102 Pa
Reynolds’ number is given by the relation:
Reynolds’ number is about 0.3. Hence, the flow is laminar.