Question -
Answer -
Volume of the room, V = 25.0 m3
Temperature of the room, T = 270 C= 300 K
Pressure in the room, P = 1 atm = 1 x 1.013 x 105 Pa
The ideal gas equation relating pressure (P), Volume (V), andabsolute temperature (T) can be written as:
PV = (kBNT)
Where,
KB isBoltzmann constant = (1.38 x 10-23) m2 kg s-2 K-1
N is the number of air molecules in the room
Therefore,
N = (PV / kBT)
= (1.013 x 105 x25) / (1.38 x 10-23 x 300)
We get,
= 6.11 x 1026 molecules
Hence, the total number of air molecules in the given room is6.11 x 1026