Question -
Answer -
Diameter of an oxygen molecule, d = 3 Å
Radius, r = d / 2
r = 3 / 2 = 1.5 Å = 1.5 x 10 -8 cm
Actual volume occupied by 1 mole of oxygen gas at STP = 22400 cm3
Molecular volume of oxygen gas, V = 4 / 3 πr3. N
Where, N is Avogadro’s number = 6.023 x 1023 molecules/mole
Hence,
V = 4 / 3 x 3.14 x (1.5 x 10-8)3 x 6.023 x 1023
We get,
V = 8.51 cm3
Therefore, ratio of the molecular volume to the actual volume ofoxygen = 8.51/ 22400 = 3. 8 x 10-4