Question -
Answer -
Given
Temperature of the helium atom, THe = -200 C= 253 K
Atomic mass of argon, MAr = 39.9 u
Atomic mass of helium, MHe = 4.0 u
Let (Vrms)Ar be the rms speedof argon and
Let (Vrms)He be the rms speedof helium
The rms speed of argon is given by:
(Vrms)Ar = √3RTAr / MAr ………… (i)
Where,
R is the universal gas constant
TAr istemperature of argon gas
The rms speed of helium is given by:
(Vrms)He = √3RTHe / MHe ………… (ii)
Given that,
(Vrms)Ar = (Vrms)He
√3RTAr /MAr = √3RTHe / MHe
TAr /MAr = THe / MHe
TAr =THe / MHe x MAr
= (253 / 4) x 39.9
We get,
= 2523.675
= 2.52 x 103 K
Hence, the temperature of the argon atom is 2.52 x 103 K