The Total solution for NCERT class 6-12
Total work done by the gas from D to E to F = Area of ∆DEF
Area of ∆DEF = (1/2) x DE x EF
Where,
DF = Change in pressure
= 600 N/m2 –300 N/m2
We get,
= 300 N/ m2
FE = Change in volume
= 5.0 m3 –2.0 m3
= 3.0 m3
Area of ∆DEF = (1/ 2) x 300 x 3
On further calculation, we get,
= 450 J
Hence, the total work done by the gas from D to E to F is 450 J