The Total solution for NCERT class 6-12
Temperature inside the refrigerator, T1┬а=90┬аC
= 273 + 9
= 282 K
Room temperature, T2┬а= 360┬аC
= 273 + 36
= 309 K
Coefficient of performance = (T1) / (T2┬атАУT1)
On substituting, we get,
= 282 / (309 тАУ 282)
We get,
= 10.44
Hence, the coefficient of performance of the given refrigeratoris 10.44