The Total solution for NCERT class 6-12
A jet airplane travelling at the speed of 500 km/h ejects its products ofcombustion at the speed of 1500 km/h relative to the jet plane. What isthe speed of the latter with respect to an observer on the ground?
Speed of the jetairplane, VA= 500 km/h
Speed at which thecombustion products are ejected relative to the jet plane, VB –VA
= – 1500 km/h
(The negative sign indicatesthat the combustion products move in a direction opposite to that of jet)
Speed of combustionproducts w.r.t. observer on the ground, VB – 500 = – 1500
VB = –1500 + 500 = – 1000 km/h