MENU
Question -

A gas inequilibrium has uniform density and pressure throughout its volume. This isstrictly true only if there are no external influences. A gas column undergravity, for example, does not have a uniform density (and pressure). Asyou might expect, its density decreases with height. The precisedependence is given by the so-called law of atmospheres
n2= n1 exp[ -mg (h2 – h1)/ kBT]
where n2, nreferto number density at heights handh1
respectively. Use this relationto derive the equation for sedimentation equilibrium of a suspension in a
liquid column:
n2 = n1 exp[ -mg NA (ρ – ρ′) (h2–h1)/ (ρ RT)]
where ρ is the density of thesuspended particle, and ρ′ ,that of surrounding medium. [NA is Avogadro’snumber, and R the universal gas constant.] [Hint : Use Archimedes principleto find the apparent weight of the suspended particle.]



Answer -

Law of atmosphere

n2= n1 exp [ -mg (h2 – h1)/ kBT] ———(1)

The suspended particle experiences an apparent weight because ofthe liquid displaced

According to Archimedes principle

Apparent weight = Weight of the water displaced – weight of thesuspended particle

= mg – m’g

= mg – Vρ’g  = mg – (m/ρ) ρ’g

= mg (1 – (ρ’/ρ)) ——-(2)

ρ′= Density of the water
ρ = Density of the suspended particle
m′ = Mass of the suspended particle
m = Mass of the water displaced
V =  Volume of a suspended particle

Boltzmann’s constant (K) = R/NA ——(3)

Substituting equation (2) and equation (3) in equation (1)

n2= n1 exp [ -mg (h2 – h1)/ kBT]

n2 =n1 exp [ -mg (1– ρ′/ ρ ) (h2–h1)NA / (RT)]

n2 =n1 exp [ -mg NA (ρ – ρ′ ) (h2–h1)/ (ρ RT)]

Comment(S)

Show all Coment

Leave a Comment

Free - Previous Years Question Papers
Any questions? Ask us!
×