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Question -

A fighter plane flying horizontally at analtitude of 1.5 km with speed 720 km/h passes directly overhead ananti-aircraft gun. At what angle from the vertical should the gun be fired forthe shell with muzzle speed 600 m s–1 tohit the plane? At what minimum altitude should the pilot fly the plane to avoidbeing hit? (Take =10 m s–2).



Answer -

Height of the fighter plane = 1.5 km = 1500 m

Speed of the fighter plane, = 720 km/h = 200 m/s

Let θ bethe angle with the vertical so that the shell hits the plane. The situation isshown in the given figure.

Muzzle velocity of the gun, u =600 m/s

Time taken by the shell to hit the plane = t

Horizontal distance travelled by the shell = uxt

Distance travelled by the plane = vt

The shellhits the plane. Hence, these two distances must be equal.

uxt = vt

In order to avoid being hit by the shell,the pilot must fly the plane at an altitude (H) higher than the maximum heightachieved by the shell.

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