Question -
Answer -
Given the difference between the two acuteangles of a right-angled triangle is 2π/5 radians.
We know that π rad =180° ⇒ 1rad = 180°/ π
Given:
2π/5
(2π/5 × 180/ π) o
Substituting thevalue of π = 22/7
(2×22/(7×5) × 180/22× 7)
(2/5 × 180) °
72°
Let one acute anglebe x° and the other acute angle be 90° – x°.
Then,
x° – (90° – x°) =72°
2x° – 90° = 72°
2x° = 72° + 90°
2x° = 162°
x° = 162°/ 2
x° = 81° and
90° – x° = 90° – 81°
= 9°
∴The angles are 81o and 9o