Question -
Answer -
Let the angles of the triangle be (a – d)°, a° and (a + d) °.
We know that, thesum of the angles of a triangle is 180°.
a – d + a + a + d =180°
3a = 180°
a = 60°
Given:
Number of degrees inthe least angle / Number of degrees in the mean angle = 1/120
(a-d)/a = 1/120
(60-d)/60 = 1/120
(60-d)/1 = 1/2
120-2d = 1
2d = 119
d = 119/2
= 59.5
∴The angles are:
(a – d) ° = 60° –59.5° = 0.5°
a° = 60°
(a + d) ° = 60° +59.5° = 119.5°
Angles of triangle in radians:
(0.5 × π/180) rad =π/360
(60 × π/180) rad = π/3
(119.5 × π/180) rad= 239π/360