Question -
Answer -
Given:
One angle of atriangle is 2x/3 grades and another is 3x/2 degree while the third is πx/75radians.
We know that, 1 grad= (9/10) o
2/3x grad = (9/10)(2/3x) o
= 3/5xo
We know that, π rad= 180° ⇒ 1rad = 180°/ π
Given: πx/75
(πx/75 × 180/π) o
(12/5x) o
We know that, the sum of the angles of a triangle is 180°.
3/5xo + 3/2xo +12/5xo = 180o
(6+15+24)/10xo = 180o
Uponcross-multiplication we get,
45xo = 180o ×10o
= 1800o
xo = 1800o/45o
= 40o
∴ Theangles of the triangle are:
3/5xo = 3/5 × 40o =24o
3/2xo = 3/2 × 40o =60o
12/5 xo = 12/5 × 40o =96o