Question -
Answer -
Given:
One angle of atriangle is 2x/3 grades and another is 3x/2 degree while the third is ╧Аx/75radians.
We know that, 1 grad= (9/10)┬аo┬а
2/3x grad = (9/10)(2/3x)┬аo
= 3/5xo
We know that, ╧А rad= 180┬░┬атЗТ┬а1rad = 180┬░/ ╧А
Given: ╧Аx/75
(╧Аx/75 ├Ч 180/╧А)┬аo
(12/5x)┬аo
We know that, the sum of the angles of a triangle is 180┬░.
3/5xo┬а+ 3/2xo┬а+12/5xo┬а= 180o
(6+15+24)/10xo┬а= 180o
Uponcross-multiplication we get,
45xo┬а= 180o┬а├Ч10o
= 1800o
xo┬а= 1800o/45o
= 40o
тИ┤┬аTheangles of the triangle are:
3/5xo┬а= 3/5 ├Ч 40o┬а=24o
3/2xo┬а= 3/2 ├Ч 40o┬а=60o
12/5 xo┬а= 12/5 ├Ч 40o┬а=96o