MENU
Question -

Find the vertex, focus, axis,directrix and lotus тАУ rectum of the following parabolas
(i) y2┬а= 8x

(ii) 4x2┬а+ y = 0

(iii) y2┬атАУ 4y тАУ 3x+ 1 = 0

(iv) y2┬атАУ 4y + 4x= 0

(v) y2┬а+ 4x + 4y тАУ3 = 0



Answer -

(i)┬аy2┬а= 8x

Given:

Parabola = y2┬а= 8x

Now by comparing with the actual parabola y2┬а=4ax

Then,

4a = 8

a = 8/4 = 2

So, the vertex is (0, 0)

The focus is (a, 0) = (2, 0)

The equation of the axis is y = 0.

The equation of the directrix is x = тАУ a i.e., x = тАУ 2

The length of the latus rectum is 4a = 8.

(ii)┬а4x2┬а+ y = 0

Given:

Parabola => 4x2┬а+ y = 0

Now by comparing with the actual parabola y2┬а=4ax

Then,

4a = ┬╝

a = 1/(4 ├Ч 4)

= 1/16

So, the vertex is (0, 0)

The focus is = (0, -1/16)

The equation of the axis is x = 0.

The equation of the directrix is y = 1/16

The length of the latus rectum is 4a = ┬╝

(iii)┬аy2┬атАУ 4y тАУ 3x + 1 = 0

Given:

Parabola y2┬атАУ 4y тАУ 3x + 1 = 0

y2┬атАУ 4y = 3x тАУ 1

y2┬атАУ 4y + 4 = 3x + 3

(y тАУ 2)2┬а= 3(x + 1)

Now by comparing with the actual parabola y2┬а=4ax

Then,

4b = 3

b = ┬╛

So, the vertex is (-1, 2)

The focus is = (3/4 тАУ 1, 2) = (-1/4, 2)

The equation of the axis is y тАУ 2 = 0.

The equation of the directrix is (x тАУ c) = -b

(x тАУ (-1)) = -3/4

x = -1 тАУ ┬╛

= -7/4

The length of the latus rectum is 4b = 3

(iv)┬аy2┬атАУ 4y + 4x = 0

Given:

Parabola y2┬атАУ 4y + 4x = 0

y2┬атАУ 4y = тАУ 4x

y2┬атАУ 4y + 4 = тАУ 4x + 4

(y тАУ 2)2┬а= тАУ 4(x тАУ 1)

Now by comparing with the actual parabola y2┬а=4ax => (y тАУ a)2┬а= тАУ 4b(x тАУ c)

Then,

4b = 4

b = 1

So, the vertex is (c, a) = (1, 2)

The focus is (b + c, a) = (1-1, 2) = (0, 2)

The equation of the axis is y тАУ a = 0 i.e., y тАУ 2 = 0

The equation of the directrix is x тАУ c = b

x тАУ 1 = 1

x = 1 + 1

= 2

Length of latus rectum is 4b = 4

(v)┬аy2┬а+ 4x + 4y тАУ 3 = 0

Given:

The parabola y2┬а+ 4x + 4y тАУ 3 = 0

y2┬а+ 4y = тАУ 4x + 3

y2┬а+ 4y + 4 = тАУ 4x + 7

(y + 2)2┬а= тАУ 4(x тАУ 7/4)

Now by comparing with the actual parabola y2┬а=4ax => (y тАУ a)2┬а= тАУ 4b(x тАУ c)

Then,

4b = 4

b = 4/4 = 1

So, The vertex is (c, a) =┬а(7/4, -2)

The focus is (- b + c, a) = (-1 + 7/4, -2) = (3/4, -2)

The equation of the axis is y тАУ a = 0 i.e., y + 2 = 0

The equation of the directrix is x тАУ c = b

x тАУ 7/4 = 1

x = 1 + 7/4

= 11/4

Length of latus rectum is 4b = 4.

Comment(S)

Show all Coment

Leave a Comment

Free - Previous Years Question Papers
Any questions? Ask us!
×