Question -
Answer -
Given:
The point (-3, 1)
Eccentricity = √(2/5)
Now let us find the equation to the ellipse.
We know that the equation of the ellipse whose axes are xand y – axis is given as
…. (1)
Now let us substitute equation (2) in equation (1), we get
It is given that the curve passes through the point (-3, 1).
So by substituting the point in the curve we get,
3(- 3)2 + 5(1)2 = 3a2
3(9) + 5 = 3a2
32 = 3a2
a2 = 32/3
From equation (2)
b2 = 3a2/5
= 3(32/3) / 5
= 32/5
So now, the equation of the ellipse is given as:
3x2 + 5y2 = 32
∴ The equation of the ellipse is 3x2 +5y2 = 32.