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Question -

Find the degree measure corresponding to the following radian measures (Use π = 22/7)
(i) 9π/5 (ii) -5π/6 (iii) (18π/5)c (iv) (-3)c (v) 11c (vi) 1c



Answer -

We know that π rad = 180°  1 rad = 180°/ π

(i)  9π/5 

[(180/π) ×(9π/5)] o

Substituting the value of π = 22/7

[180/22 × 7× 9 × 22/(7×5)]

(36 × 9) °

324°

Degree measure of 9π/5 is 324°

(ii) -5π/6 

[(180/π) ×(-5π/6)] o

Substituting the value of π = 22/7

[180/22 × 7× -5 × 22/(7×6) ]

(30 × -5) °

– (150) °

Degree measure of -5π/6 is -150°


(iii) (18π/5)

[(180/π) ×(18π/5)] o

Substituting the value of π = 22/7

[180/22 × 7× 18 × 22/(7×5)]

(36 × 18) °

648°

Degree measure of 18π/5 is 648°

(iv) (-3) c 

[(180/π) ×(-3)] o

Substituting thevalue of π = 22/7

[180/22 × 7× -3] o

(-3780/22) o

(-171 18/22) o

(-171 o (18/22 × 60)’)

(-171o (49 1/11)’)

(-171o 49′ (1/11 × 60)’)

– (171° 49′ 5.45”)

≈ – (171° 49′ 5”)

Degree measure of (-3) c is -171° 49′ 5”

(v) 11c

(180/ π × 11) o

Substituting the value of π = 22/7

(180/22 × 7 × 11) o

(90 × 7) °

630°

Degree measure of 11c is 630°

(vi) 1c

(180/ π × 1) o

Substituting thevalue of π = 22/7

(180/22 × 7 × 1) o

(1260/22) o

(57 3/11) o

(57o (3/11 × 60)’)

(57o (16 4/11)’)

(57o 16′ (4/11 × 60)’)

(57o 16′ 21.81”)

≈ (57o 16′ 21”)

Degree measure of 1c is 57o 16′ 21”

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