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Question -

Find the area of the triangle formed by the lines joining the vertex of the parabola x2 = 12y to the ends of its latus – rectum.



Answer -

Given:

The parabola, x2 = 12y

Now, let us compare to the actual parabola, y2 =4ax

Then,

Vertex is O(0, 0)

Ends of latus rectum is (2b, b), (-2b, b)

4b = 12

b = 12/4

= 3

Ends of latus rectum = (2(3), 3), (- 2(3), 3)

Ends of latus rectum is A(6, 3), B(- 6, 3)

We know that area of the triangle with the vertices (x1,y1), (x2, y2) and (x3, y3)is

The area of the triangle is 18 sq.units.

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