The Total solution for NCERT class 6-12
Given:
The parabola, x2 = 9y
Let us assume the point be (3y1, y1).
Now by substituting the point in the parabola we get,
(3y1)2 = 9(y1)
9y12 = 9y1
y12 – y1 = 0
y1(y1 – 1) = 0
y1 = 0 or y1 – 1 = 0
y1 = 0 or y1 = 1
The points is B (3(1), 1) => (3, 1)
∴The point is (3, 1).