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Chapter 8 Redox Reactions Solutions

Question - 11 : - (a) Though alkaline potassium permanganate and acidic potassiumpermanganate both are used as oxidants, yet in the manufacture of benzoic acidfrom toluene, we use alcoholic potassium permanganate as an oxidant, why ?Write a balanced redox equation for the reaction.

(b) When concentrated sulphuric acid is added to an inorganicmixture containing chloride, we get a colourless pungent smelling gas HC1.However, if mixture contains bromide, then red vapours of bromine are evolved.Why ?

Answer - 11 : -

In the manufacture ofbenzoic acid from toluene, neutral medium is preferred over acidic or alkalinemedium due to following reasons.

·         In the neutralmedium, neither acid or base is to be added externally. This will definitelyreduce the cost of the manufacturing process.

·        Alcohol if used assolvent will help in the formation of a homogeneous mixture between toluene(non-polar) and KMnO(ionic). Actually alcohol has non-polaralkyl group as well as polar OH group.

(b)
A chloride such as NaClreacts with concentrated sulphuric acid to evolve hydrogen chloride gas uponheating. It has a pungent smell.
Hydrogen bromide is also expected to be formed in the same way when abromide is heated with concentrated sulphuric acid. However, the acid being astrong oxidising agent will oxidise HBr to bromine (Br2) which getsevolved  as red vapours.

Please note HC1 (g) isquite stable and is not oxidised to chlorine with concentrated sulphuric acid.

Question - 12 : -

Identify the substance oxidised, reduced, oxidising agent and reducingagent for each of the following reactions :

1.   2AgBr(s) + C6H6O2(aq)→2Ag(s) + 2HBr(aq) + C6H4O2(aq)

2.   HCHO(l) + 2[Ag(NH3)2]+(aq)+ 3OH(aq) → 2Ag(s) + HCOO (aq) + 4NH3(aq)+ 2H2O(l)

3.   HCHO(l) + 2Cu2+(aq)+ 5OH(aq)→ Cu2(O(s) + HCOO-(aq) + 3H2O(l)

4.   N2H4(l)+ 2H2O2(l) →N2(g) + 4H2O(l)

5.   Pb(s) + PbO2(s)+ 2H2SO4(aq)→ 2PbSO4(s) + 2H2O(l)

Answer - 12 : -

AgBr        : reduced ; acts as oxidising agent
C6H6O2    : oxidised ; acts asreducing agent.

Question - 13 : - Consider the reactions :
2S2O2-3(aq) + I2(s) → S4O2-6(aq)+ 2I(aq)
S2O(aq) + 2Br2(l) + 5H2O (l)→ 2SO2-4(aq) + 4Br-(ag) + 10H +(aq)
Why does the same reductant the osulphate react differently with iodine andbromine ?

Answer - 13 : - I2 oxidises thiosulphate ion to tetrathionate ion i.e.,from O.S. of + 2 for S (in S2O2-3 ) toS.O. of + 5/2 for S (in S4O2-4 ion).
Br2 oxidises thiosulphate ion to sulphate ion i.e., fromO.S. of + 2 for S (in S2O2-3) to O.S. of + 6for S
(in SO2-4 ion)
This is because Br2 is a stronger

Question - 14 : - Justify giving reactions that among halogens, fluorine is the bestoxidant and among hydrohalic compounds, hydroiodic acid is the best reductant.

Answer - 14 : - The halogens (X2) have strong electron accepting tendency.They are therefore, powerful oxidising agents. The relative order of oxidisingpowers of halogens is :

Fluorine is the strongest oxidising agent (oxidant). It can be justifiedby the fact that it can liberate the other halogens from their respectivecompounds. For example,
2KC1 + F2  →  2KF + Cl2
2KBr + F2 → 2KF + Br2
2KI + F2 → 2KF + I2
Among halogen acids (HX), the HI is the strongest reducing agent orreductant because its bond dissociation enthalpy is the minimum (299 kJ mol-1)
(kJ mol-1)
The iodination of methane for examples, is of reversible nature because HIformed in the reaction being a very strong reducing agent converts iodomethaneback to methane

However, thehalogenation with other halogen acids is not of reversible nature. Thisjustifies that HI is the strongest reducing agent in the halogen acids.

Question - 15 : - Why does the following reaction occur ?
XeO4-6 (aq) + 2F(aq) + 6H+(aq)→XeO3(g) + 3H2O(l)
What conclusion about the compound Na4XeO6 (of whichXeO4-6 is a part can be drawn from the reaction ?

Answer - 15 : -

In the reaction, O.N.of Xe decreases from + 8 to + 6. Therefore, XeO6 isreduced.O.N. of F increases from – 1 to 0. Therefore, F isoxidised. The redox reaction occurs because Na2XeO6 (ofwhich XeOg“ is a part) is a stronger oxidising agent than F2.

Question - 16 : - Consider the reactions :
(a) H3PO2 (aq)+ 4AgNO3 (aq) + 2H2O (l)→H3PO4 (aq)+ 4Ag (s) + 4HNO3 (aq)
(b) H3PO2 (aq) + 2CuSQ4 (aq) + 2H2O(l)→ H3PO4 (aq) + 2Cu (s) + 2H2SO4 (aq)
(c) C6H5CHO (I) + 2[Ag(NH3)2+ (aq)+ 3OH (aq)→ C6H5COO (aq) + 2Ag (s) + 4NH3 (aq)+ 2H2O (l)
(d) C6H5CHO (l) + 2Cu2+(aq) + SOH(aq)→Nochange observed
What inference do you draw about the behaviour of Ag+ and Cu2+ ionsfrom these reactions ?

Answer - 16 : -

(a) Hypophosphorusacid (H3PO2) reduces Ag+ ions to Ag whichgets precipitated
(b) Hypophosphorus acid (H3PO2)reduces Cu2+ ions to Cu which gets precipitated
(C) Benzaldehyde (C6H5CHO)reduces Ag+ions to Ag which gets precipitated
(d) Benzaldehyde (C6H5CHO)is not in a position to reduce Cu2+ ions to Cu.
This shows that Ag+ ions are stronger oxidising agent than Cu2+ ionsin all the reactions. This is quite evident from their relative positions inthe reactivity series.

Question - 17 : - Balance the following equations byion-electron method

Answer - 17 : -

Question - 18 : - Balance the following equations in basic medium by ion-electron methodand oxidation number method and identify the oxidising agent and the reducingagent.
(a) p4(s) + OH+(aq) —> PH3(g) + H2PO2 (aq)
(b) N2H4(7) + CIO3 (aq) —>NOfe) + C l(g)
(c) C12O7(g) + H2O2(aq) —> CIO2(aq)+ O2(g) + H

Answer - 18 : -

Question - 19 : - Write four informations about the reaction :
(CN)2 (g) + 2OH (aq)—> CN (aq)+ CNO (aq) + H2O (l).

Answer - 19 : -

1.   The reaction involvesthe decomposition of cyanogen (CN)2 in the alkaline medium.

2.   Both (CN)2 i.e.cyanogen and CN i.e. cyanide ions are pseudo halogens innature i.e. they behave like halogens in characteristics.

3.   Cyanogen undergoesdisproportionation in the reaction. It undergoes simultaneous increase anddecrease in O.N.of the species involved.

4.   It is an example ofredox reaction.

Question - 20 : - The Mn3+ ion is unstable in solution and under goesdisproportionation to give Mn2+, MnO2 and H+ ion.Write balanced ionic equation for the reaction.

Answer - 20 : -

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