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Question -

Whatis the equilibrium concentration of each of the substances in the equilibriumwhen the initial concentration of ICl was 0.78 M?

2 ICl(g) ⇌  I2(g) + Cl2(g) ; KC = 0.14



Answer -

Thegiven reaction is:

2 ICl(g)    ⇌   I2(g)  +  Cl2(g) Initialconc.               0.78 M          0           0 Atequilibrium         (0.78 – 2x)M     x M        x M

Hence,at equilibrium,

[ICl]=[I2] = 0.167 M[ICl] = (0.78 -2×0.167)M        =0.446 M 

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