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Question -

The ionization constant of acetic acid is1.74 × 10–5. Calculate the degree of dissociation ofacetic acid in its 0.05 M solution. Calculate the concentration of acetate ionin the solution and its pH.



Answer -

Method 1

Since Ka >> Kw, :

Method 2

Degreeof dissociation,

c = 0.05 M

Ka = 1.74 × 10–5

Thus, concentration of CH3COO– = c.α

Hence,the concentration of acetate ion in the solution is 0.00093 M and its Ph is3.03.

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