The Total solution for NCERT class 6-12
Step I Calculation of the mass of displaced airRadius of balloon (r) = 10 mVolume of balloon (V) = 4 πr3 = 4 × 22 ×(10 m)3 = 4190.5 m3Mass of the displaced air = Volume of air (balloon) × Density of air= (4190.5 m3) × (1.2 kg m-3) = 5028.6 kgStep II Calculation of the mass of the filled balloon.=279.37 × 103 mol.Mass of He present = Moles of He × Molar mass of He= (279.37 × 103 mol) × (4 g mol-1)= 1117.48 × 103g = 1117.48 kgMass of filled balloon = 100 + 1117.48 = 1217.48 kgStep III. Calcu lation of the pay loadPay load = Mass of displaced air – Mass of filled balloon= 5028.6 – 1217.48 =3811.12 kg.
=279.37 × 103 mol.Mass of He present = Moles of He × Molar mass of He= (279.37 × 103 mol) × (4 g mol-1)= 1117.48 × 103g = 1117.48 kgMass of filled balloon = 100 + 1117.48 = 1217.48 kgStep III. Calcu lation of the pay loadPay load = Mass of displaced air – Mass of filled balloon= 5028.6 – 1217.48 =3811.12 kg.