Question -
Answer -
Thegiven reaction is:
Now,2 mol of NOBr are formed from 2 mol of NO. Therefore, 0.0518 mol of NOBr areformed from 0.0518 mol of NO.
Again,2 mol of NOBr are formed from 1 mol of Br.
Therefore,0.0518 mol of NOBr are formed from
molof Br, or
0.0259mol of NO.
Theamount of NO and Br present initially is as follows:
[NO] = 0.087 mol [Br2] = 0.0437 mol
Therefore,the amount of NO present at equilibrium is:
[NO]= 0.087 – 0.0518
=0.0352 mol
And,the amount of Br present at equilibrium is:
[Br2] = 0.0437 – 0.0259
=0.0178 mol