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Question -

For the reaction at 298 K,

2A + B → C

ΔH = 400 kJ mol–1 and ΔS =0.2 kJ K–1 mol–1

At what temperature will the reaction becomespontaneous considering ΔH and ΔS to be constant overthe temperature range?



Answer -

From the expression,

ΔG = ΔH – TΔS

Assuming the reaction at equilibrium, ΔT forthe reaction would be:

 (ΔG = 0 at equilibrium)

T = 2000 K

Forthe reaction to be spontaneous, ΔG must be negative. Hence, for thegiven reaction to be spontaneous, T should be greater than2000 K.

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