The Total solution for NCERT class 6-12
Find out the value of Kc for each of thefollowing equilibria from the value of Kp:
The relation between Kp and Kc is given as:
Kp = Kc (RT)Δn
(a) Here,
Δn = 3 – 2 = 1
R = 0.0831 barLmol–1K–1
T = 500 K
Kp = 1.8 × 10–2
Now,
Kp = Kc (RT) Δn
(b) Here,
Δn = 2 – 1 = 1
T = 1073 K
Kp= 167