The Total solution for NCERT class 6-12
Energy of an electron in the ground state ofthe hydrogen atom is –2.18 × 10–18 J. Calculate the ionization enthalpy ofatomic hydrogen in terms of J mol–1.
It is given that the energy of an electron inthe ground state of the hydrogen atom is –2.18 × 10–18 J.
Therefore, the energy required to remove that electronfrom the ground state of hydrogen atom is 2.18 × 10–18 J.
Ionizationenthalpy of atomic hydrogen = 2.18 × 10–18 J
Hence, ionization enthalpy of atomic hydrogen in terms ofJ mol–1 = 2.18 × 10–18 ×6.02 × 1023 J mol–1 =1.31 × 106 J mol–1