Question -
Answer -
The first five membersof each homologous series beginning with the given compounds are┬аshown asfollows:
(a)
HтАУCOOH : Methanoic acid
CH3тАУCOOH :Ethanoic acid
CH3тАУCH2тАУCOOH: Propanoic acid
CH3тАУCH2тАУCH2тАУCOOH: Butanoic acid
CH3тАУCH2тАУCH2тАУCH2тАУCOOH: Pentanoic acid
(b)
CH3COCH3┬а:Propanone
CH3COCH2CH3┬а:Butanone
CH3COCH2CH2CH3┬а:Pentan-2-one
CH3COCH2CH2CH2CH3┬а:Hexan-2-one
CH3COCH2CH2CH2CH2CH3┬а:Heptan-2-one
(c)
HтАУCH=CH2┬а:Ethene
CH3тАУCH=CH2┬а:Propene
CH3тАУCH2тАУCH=CH2┬а:1-Butene
CH3тАУCH2тАУCH2тАУCH=CH2┬а:1-Pentene
CH3тАУCH2тАУCH2тАУCH2тАУCH=CH2┬а:1-Hexene