Question -
Answer -
(i) Balancing the given chemical equation,
From the equation, 1 mole (28 g) of dinitrogen reacts with3 mole (6 g) of dihydrogen to give 2 mole (34 g) of ammonia.
⇒2.00 × 103 g of dinitrogen will react with 
dihydrogen i.e.,
2.00 × 103 g of dinitrogenwill react with 428.6 g of dihydrogen.
Given,
Amount of dihydrogen = 1.00 × 103 g
Hence, N2 is the limitingreagent.
28 g of N2 produces34 g of NH3.
Hence, mass of ammonia produced by 2000 g of N2
= 2428.57 g
(ii) N2 is the limitingreagent and H2 is the excess reagent. Hence, H2 willremain unreacted.
(iii) Mass of dihydrogen left unreacted =1.00 × 103 g – 428.6 g
= 571.4 g