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Question -

Consider the following species:

N3тАУ, O2тАУ, FтАУ, Na+, Mg2+┬аand Al3+

(a) What is common in them?

(b) Arrange them in the order of increasingionic radii.

┬а



Answer -

(a) Each of the given species (ions) has the same numberof electrons (10 electrons). Hence, the given species are isoelectronic.

(b) Theionic radii of isoelectronic species increases with a decrease in themagnitudes of nuclear charge.

Thearrangement of the given species in order of their increasing nuclear charge isas follows:

N3тАУ┬а< O2тАУ┬атАУ┬а< Na+┬а2+┬а< Al3+

Nuclearcharge = +7 +8 +9 +11 +12 +13

Therefore,the arrangement of the given species in order of their increasing ionic radiiis as follows:

Al3+┬а< Mg2+┬а+┬а< FтАУ┬а2тАУ┬а< N3тАУ

┬а

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