The Total solution for NCERT class 6-12
Calculatethe pH of the resultant mixtures:
a) 10 mL of 0.2M Ca(OH)2 + 25 mL of 0.1M HCl
b) 10 mL of 0.01M H2SO4 + 10 mL of 0.01MCa(OH)2
c) 10 mL of 0.1M H2SO4 + 10 mL of 0.1M KOH
(a)
Thus, excess of =.0015 mol
(b)
Since there is neither an excess of or,the solution is neutral. Hence, pH = 7.
=1.30