The Total solution for NCERT class 6-12
Calculatethe pH of the following solutions:
a)2 g of TlOH dissolved in water to give 2 litre of solution.
b) 0.3 g of Ca(OH)2 dissolved in water to give500 mL of solution.
c)0.3 g of NaOH dissolved in water to give 200 mL of solution.
d)1mL of 13.6 M HCl is diluted with water to give 1 litre of solution.
(a) For2g of TlOH dissolved in water to give 2 L of solution:
(b) For 0.3 g of Ca(OH)2 dissolved in waterto give 500 mL of solution:
(c) For 0.3 g of NaOHdissolved in water to give 200 mL of solution:
(d) For 1mL of 13.6 MHCl diluted with water to give 1 L of solution:
13.6 × 1 mL = M2 × 1000 mL
(Beforedilution) (After dilution)
13.6 × 10–3 = M2 × 1L
M2 = 1.36 × 10–2
[H+] = 1.36 × 10–2
pH = – log (1.36 × 10–2)
=(– 0.1335 + 2)
=1.866 ∼ 1.87