The Total solution for NCERT class 6-12
Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molaraqueous solution. Molar mass of sodium acetate is 82.0245 g mol–1
0.375 M aqueous solution of sodium acetate
≡ 1000 mLof solution containing 0.375 moles of sodium acetate
∴Number of moles of sodium acetate in 500 mL
Molar mass of sodium acetate = 82.0245 g mole–1 (Given)
∴ Requiredmass of sodium acetate = (82.0245 g mol–1)(0.1875 mole)
= 15.38 g