Question -
Answer -
Total enthalpy changeinvolved in the transformation is the sum of the following changes:
(a) Energy change involvedin the transformation of 1 mol of water at 10┬░C to 1 mol of water at 0┬░C.
(b) Energy change involvedin the transformation of 1 mol of water at 0┬░ to 1 mol of ice at 0┬░C.
(c) Energy change involvedin the transformation of 1 mol of ice at 0┬░C to 1 mol of ice at тАУ10┬░C.
= (75.3 J molтАУ1┬аKтАУ1) (0 тАУ 10)K + (тАУ6.03 ├Ч 103┬аJ molтАУ1) + (36.8 J molтАУ1┬аKтАУ1) (тАУ10 тАУ 0)K
= тАУ753 J molтАУ1┬атАУ 6030 J molтАУ1┬атАУ 368 J molтАУ1
= тАУ7151 J molтАУ1
= тАУ7.151 kJ molтАУ1
Hence,the enthalpy change involved in the transformation is тАУ7.151 kJ molтАУ1.