The Total solution for NCERT class 6-12
Calculate a) ΔG°and b) theequilibrium constant for the formation of NO2 from NO and O2 at 298 K
where ΔfG° (NO2) = 52.0 kJ/mol
ΔfG° (NO) = 87.0 kJ/mol
ΔfG° (O2) = 0 kJ/mol
(a) For the given reaction,
ΔG° = ΔG°( Products) – ΔG°(Reactants)
ΔG° = 52.0 – {87.0 + 0}
= – 35.0 kJ mol–1
(b) We know that,
ΔG° = RT log Kc
ΔG° = 2.303 RT log Kc
Hence,the equilibrium constant for the given reaction Kc is 1.36 × 106