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Question -

Avessel of 120 mL capacity contains a certain amount of gas at 35°C and 1.2 barpressure. The gas is transferred to another vessel of volume 180 mL at 35°C.What would be its pressure?



Answer -

V1= 120 mL, P1=1.2 bar,
V2 = 180 mL, P2 = ?
As temperature remains constant, P1V1 =P2V2
(1.2 bar) (120 mL) = P2 (180mL)

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